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How do you solve #-10z ^ { 2} = 11z - 6#? - Socratic
(2/5) and (-3/2) f(z) = 10z^2 + 11z - 6 = 0 Solve it by the new transforming method (Socratic Search) Method. First, find 2 real roots of the transformed equation. f'(z) = z^2 + 11z - 60 = 0. Next divide …
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